Crystal structure of PbUO2(CH3COO)(4)(H2O)(3)

Single crystals of PbUO2(CH3COO)(4)(H2O)(3) have been investigated by X-ray diffraction (R = 0.029 for 3175 reflections). The structure of this compound is formed by [Pb(CH3COO)(H2O)(3)](+) chains, which are oriented along the [100] axis and limited by one-core complexes [UO2(CH3COO)(3)](-). The coordination numbers of the Pb(II) and U(VI) atoms are 8, and the coordination polyhedron of uranium is a hexagonal bipyramid whose vertices contain oxygen atoms of three bidentate cyclic acetate groups and the uranyl group. Taking into account the different crystallographic roles of acetate ions, the crystal-chemical formula of [PbUO2(CH3COO)(4)(H2O)(3)] chains can be written as AA'B (21) B (11)(B (01))(2) M (3) (1) , where A = Pb; A' = UO (2) (2+) ; M (1) = H2O; and B (21), B (11), and B (01) are CH3COO- groups.